How to show link button datagridview windows application ?

//Create instance for datagrid view link column class
DataGridViewLinkColumn link = new DataGridViewLinkColumn();
link.UseColumnTextForLinkValue = true;
//Enter your link button column header text
link.HeaderText = "Click to View Details";
//set the property name for link column
link.DataPropertyName = "lnkColumn";
//set default active color for link
link.ActiveLinkColor = Color.White;
link.LinkBehavior = LinkBehavior.SystemDefault;
//set default link color 
link.LinkColor = Color.Blue;
//set default link text
link.Text = "View Details";            

//set visited color means if user click that link what color would be change
link.VisitedLinkColor = Color.YellowGreen;
//Add this link column to datagrid view
dataGridView1.Columns.Add(link);
 

private void dataGridView1_CellContentClick(object sender, DataGridViewCellEventArgs e)
{
    //Check whether user click on the first column 
    if (e.ColumnIndex == 0)
    {
        int row;
        //Get the row index
        row = e.RowIndex;
        //Create instance of the form2 class
        Form2 obj = new Form2();
        //Bind the datagridview values in the second popup form
        obj.Controls["TextBox1"].Text = dataGridView1.Rows[row].Cells[1].Value.ToString();
        obj.Controls["TextBox2"].Text = dataGridView1.Rows[row].Cells[2].Value.ToString();
        obj.Controls["TextBox3"].Text = dataGridView1.Rows[row].Cells[3].Value.ToString();
        obj.ShowDialog();
    }
}

create table emp(eno int,empname varchar(50),sal bigint)
insert into emp values(101,'ravi','25000')
insert into emp values(102,'john','18000')
insert into emp values(103,'joseph','10000')
 

using System.Data;

namespace DGV_lnkButton
{
    public partial class Form1 : Form
    {
        SqlConnection sqlcon = new SqlConnection(@"server=RAVI-PC\SQLEXPRESS;database=test1;uid=xxx;pwd=yyy;");
        SqlCommand sqlcmd = new SqlCommand();
        SqlDataAdapter da = new SqlDataAdapter();
        DataTable dt = new DataTable();

        public Form1()
        {
            InitializeComponent();
        }
        private void Form1_Load(object sender, EventArgs e)
        {
            //Create instance for datagrid view link column class
            DataGridViewLinkColumn link = new DataGridViewLinkColumn();
            link.UseColumnTextForLinkValue = true;
            //Enter your link button column header text
            link.HeaderText = "Click to View Details";
            //set the property name for link column
            link.DataPropertyName = "lnkColumn";
            //set default active color for link
            link.ActiveLinkColor = Color.White;
            link.LinkBehavior = LinkBehavior.SystemDefault;
            //set default link color 
            link.LinkColor = Color.Blue;
            //set default link text
            link.Text = "View Details";            
           
            //set visited color means if user click that link what color would be change
            link.VisitedLinkColor = Color.YellowGreen;
            //Add this link column to datagrid view
            dataGridView1.Columns.Add(link);

            //Open connection
            sqlcon.Open();
            //pass query 
            sqlcmd = new SqlCommand("select * from emp",sqlcon);
            da = new SqlDataAdapter(sqlcmd);
            //Fill the data in the SQL Data Adapter
            da.Fill(dt);
            //Bind it in the DataGrid View
            dataGridView1.DataSource = dt;
            sqlcon.Close();
            
            //Uncomment below line when you want display link column at last
            //dataGridView1.Columns[0].DisplayIndex = 3;
        }

        private void dataGridView1_CellContentClick(object sender, DataGridViewCellEventArgs e)
        {
            //Check whether user click on the first column 
            if (e.ColumnIndex == 0)
            {
                int row;
                //Get the row index
                row = e.RowIndex;
                //Create instance of the form2 class
                Form2 obj = new Form2();
                //Bind the datagridview values in the second popup form
                obj.Controls["TextBox1"].Text = dataGridView1.Rows[row].Cells[1].Value.ToString();
                obj.Controls["TextBox2"].Text = dataGridView1.Rows[row].Cells[2].Value.ToString();
                obj.Controls["TextBox3"].Text = dataGridView1.Rows[row].Cells[3].Value.ToString();
                obj.ShowDialog();
            }
        }
    }
}