How to show uploaded images in Grid view ?

How to add new record in to the grid view?
Starting we have add new record into the database like this way convert images into bytes and insert into the database.

if (FileUpload1.HasFile)
{
  sname = TextBox1.Text;
  filebyte = convertByte(FileUpload1);
  sqlcon.Open();
  query = "insert into stud(sname,simage) values(@sname,@simage)";
  SqlCommand cmd = new SqlCommand(query, sqlcon);
  cmd.Parameters.Add("@sname", SqlDbType.VarChar).Value = sname;
  cmd.Parameters.Add("@simage", SqlDbType.Image).Value = filebyte;
  cmd.CommandType = CommandType.Text;
  cmd.ExecuteNonQuery();
  sqlcon.Close();
  TextBox1.Text = "";
  LoadGrid();
}

//Convert Byte method
public byte[] convertByte(FileUpload FileControl)
{
  Stream fs = default(Stream);
  byte[] bytes1 = null;
  byte[] postfile = null;
  fs = FileControl.PostedFile.InputStream;
  BinaryReader br1 = new BinaryReader(fs);
  bytes1 = br1.ReadBytes(FileControl.PostedFile.ContentLength);
  postfile = bytes1;
  return postfile;
}

protected void GridView1_RowUpdating(object sender, GridViewUpdateEventArgs e)
{
  GridViewRow row = GridView1.Rows[e.RowIndex];
  string sid;
  sid = GridView1.DataKeys[e.RowIndex].Value.ToString();
  TextBox sname = (TextBox)row.FindControl("txtsname");
  FileUpload simage = (FileUpload)row.FindControl("FileUpload2");
  sqlcon.Open();
  query = "update stud set sname=@sname,simage=@simage where sid=@sid";
  SqlCommand cmd = new SqlCommand(query, sqlcon);
  cmd.Parameters.Add("@sname", SqlDbType.VarChar).Value = sname.Text;
  cmd.Parameters.Add("@simage", SqlDbType.Image).Value = convertByte(simage);
  cmd.Parameters.Add("@sid", SqlDbType.Int).Value = Convert.ToInt32(sid);
  cmd.CommandType = CommandType.Text;
  cmd.ExecuteNonQuery();
  sqlcon.Close();
  GridView1.EditIndex = -1;
  LoadGrid();
}