Open File Dialog Control

Here is code to use open file dialog control in a windows based application

put a File dialog control on the form and a button
and add the below code in the button click

 OpenFiledialog.Filter = "Image Files|*.jpg;*.gif;*.bmp;*.png;*.jpeg|All Files|*.*"
        OpenFiledialog.InitialDirectory = "C:\"
        OpenFiledialog.FilterIndex = 1

        OpenFiledialog.Title = "Open File"
        If (OpenFiledialog.ShowDialog() = Windows.Forms.DialogResult.OK) Then
            thumb = OpenFilephoto.FileName
            Picturephoto.Image = Image.FromFile(thumb)
        End If