Category: Webservices

31 May 2016 05:37

Joined:	29/06/2011
Level:	Silver
Points:	333

Points:	4

How to deserialize to a list object in web api

Hi All,

I have receive an data in following format of json, it is contain like \r\n

{
"Status": true,
"Message": "Success.",
"Data": null,
"RecordCount": 4,
"Collection": [
{
"Bsid": "1-XY01CC58-1",
"Code": "WEB\r\n",
"SourceName": "Web Campaign\r\n",
"Description": "b n nmjn vb nmjbv nmjbv",
"IsActive": true,
"PropertyId": null,
"UserName": null
}

#766272

31 May 2016 21:01

Joined:	22/05/2016
Level:	Bronze
Points:	17

Points:	3

//Replace escape sequences.

jsonString = jsonString.Replace(@"\r\n", " ");

//Deserialize if you are using json.NET.

SearchRootObject obj = JsonConvert.DeserializeObject<SearchRootObject>(jsonString);

//Or With JavaScriptSerializer Class.

JavaScriptSerializer().Deserialize<SearchObj.RootObject>(jsonString);

#766273

31 May 2016 21:36

Joined:	13/06/2007
Level:	Gold
Points:	21327

Points:	4

Many time JSON return '\r\n' characters, basically you need to Take your JSON and .stringify() it. Then use the .replace() method and replace all occurrences of \n with \\n.
I think there is no inbuilt library for escaping all special characters in a string, you need to customize your code as follows


var myJSONString = JSON.stringify(myJSON);
var myEscapedJSONString = myJSONString.replace(/\\n/g, "\\n")
                                      .replace(/\\'/g, "\\'")
                                      .replace(/\\"/g, '\\"')
                                      .replace(/\\&/g, "\\&")
                                      .replace(/\\r/g, "\\r")
                                      .replace(/\\t/g, "\\t")
                                      .replace(/\\b/g, "\\b")
                                      .replace(/\\f/g, "\\f");
// myEscapedJSONString is now ready to be POST'ed to the server.

Thanks
Koolprasd2003
Editor, DotNetSpider MVM
Microsoft MVP 2014 [ASP.NET/IIS]

#766274

31 May 2016 22:33

Joined:	15/12/2015
Level:	Gold
Points:	1308

Points:	2

Hi,
Just replace '\n and \r' with '' i.e. blank values, try this:


var responseText = received data;
var finalJSONResp = responseText.replace(/\\n/g, "")
                                                       .replace(/\\r/g, "");
alert(finalJSONResp);

#766275

31 May 2016 22:45

Joined:	29/05/2009
Level:	Gold
Points:	10380

Points:	2

Hi
you can go through Below links


"asp.net/web-api/overview/formats-and-model-binding/json-and-xml-serialization"
"stackoverflow.com/questions/15841309/deserializing-list-of-json-objects-in-webapi-method"

Name : Dotnet Developer-2015
Email Id : kumaraspcode2009@gmail.com

'Not by might nor by power, but by my Spirit,' says the LORD Almighty.

#766294

02 Jun 2016 00:00

Joined:	29/06/2011
Level:	Silver
Points:	333

Points:	1

Hi All of you, i want to serialize or deserialize without replace word, any other way of doing deserialize a list or collection.

Thanks & Regards,

Atul Sharma

How to deserialize to a list object in web api

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