Get the 5 th element from end of linked list

int iCount = linkedList.Count;
var value = linkedList.ElementAt(iCount  - 5);

List<string> lststr = new List<string>();
         lststr.Add("A");
         lststr.Add("B");
         lststr.Add("C");
         lststr.Add("D");
         lststr.Add("E");
         lststr.Add("F");
         lststr.Add("G");
         lststr.Add("H");

         for (int i = 0; i <= lststr.Count - 1; i++)
         {
             if (i == 5)
             {
                 //Statement
             }
         }

public SLElement Remove(int index)
{
    SLElement prev = _root;
    if(prev == null) return null; //or throw exception
    SLElement curr = _root.next;
    for(int i = 1; i < index; i++)
    {
      if(curr == null) return null; //or throw exception
      prev = curr;
      curr = curr.next;
    }
    prev.next = curr.next; //set the previous's node point to current's next node
    curr.next = null;
    return curr;
}