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Category: .NET
#765663
it is simple, The ElementAt extension method will do it, Use 'Count ' property of linkedlist to get the total number of items in the list and the get the specific location item
see below snippet
hope it helps
Thanks
Koolprasd2003
Editor, DotNetSpider MVM
Microsoft MVP 2014 [ASP.NET/IIS]
see below snippet
int iCount = linkedList.Count;
var value = linkedList.ElementAt(iCount - 5);
hope it helps
Thanks
Koolprasd2003
Editor, DotNetSpider MVM
Microsoft MVP 2014 [ASP.NET/IIS]
#766317
hi
try this code
Name : Dotnet Developer-2015
Email Id : kumaraspcode2009@gmail.com
'Not by might nor by power, but by my Spirit,' says the LORD Almighty.
try this code
List<string> lststr = new List<string>();
lststr.Add("A");
lststr.Add("B");
lststr.Add("C");
lststr.Add("D");
lststr.Add("E");
lststr.Add("F");
lststr.Add("G");
lststr.Add("H");
for (int i = 0; i <= lststr.Count - 1; i++)
{
if (i == 5)
{
//Statement
}
}
Name : Dotnet Developer-2015
Email Id : kumaraspcode2009@gmail.com
'Not by might nor by power, but by my Spirit,' says the LORD Almighty.
#766328
Hi,
Please find an algorithm written in C# to find nth element from end of linked list:
http://www.c-sharpcorner.com/uploadfile/rawatgaurav/find-nth-element-from-last-in-a-linked-list/
Please find an algorithm written in C# to find nth element from end of linked list:
http://www.c-sharpcorner.com/uploadfile/rawatgaurav/find-nth-element-from-last-in-a-linked-list/
#766348
simply you need to Loop throw index times and find the element
Thanks
Koolprasd2003
Editor, DotNetSpider MVM
Microsoft MVP 2014 [ASP.NET/IIS]
public SLElement Remove(int index)
{
SLElement prev = _root;
if(prev == null) return null; //or throw exception
SLElement curr = _root.next;
for(int i = 1; i < index; i++)
{
if(curr == null) return null; //or throw exception
prev = curr;
curr = curr.next;
}
prev.next = curr.next; //set the previous's node point to current's next node
curr.next = null;
return curr;
}
Thanks
Koolprasd2003
Editor, DotNetSpider MVM
Microsoft MVP 2014 [ASP.NET/IIS]
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