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Resources » Code Snippets » C# Syntax »

How to validate a date using c#


Posted Date: 02 Aug 2007    Resource Type: Code Snippets    Category: C# Syntax
Author: Pujitha SendanayakeMember Level: Bronze    
Rating: 1 out of 5Points: 10



This code snippet validates any date from 1800 -to 9999. Also,It handles leap years. Allowed formats are mm/dd/yyyy , m/dd/yyyy , mm/d/yyyy , m/d/yyyy.


public bool isDate(string strDate)
{
string strRegex = @"((^(10|12|0?[13578])([/])(3[01]|[12][0-9]|0?[1-9])([/])((1[8-9]\d{2})|([2-9]\d{3}))$)|(^(11|0?[469])([/])(30|[12][0-9]|0?[1-9])([/])((1[8-9]\d{2})|([2-9]\d{3}))$)|(^(0?2)([/])(2[0-8]|1[0-9]|0?[1- 9])([/])((1[8-9]\d{2})|([2-9]\d{3}))$)|(^(0?2)([/])(29)([/])([2468][048]00)$)|(^(0?2)([/])(29)([/])([3579][26]00)$)|(^(0?2)([/])(29)([/])([1][89][0][48])$)|(^(0?2)([/])(29)([/])([2-9][0-9][0][48])$)|(^(0?2)([/])(29)([/])([1][89][2468][048])$)|(^(0?2)([/])(29)([/])([2-9][0-9][2468][048])$)|(^(0?2)([/])(29)([/])([1][89][13579][26])$)|(^(0?2)([/])(29)([/])([2-9][0-9][13579][26])$))";

Regex re = new Regex(strRegex);
if (re.IsMatch(strDate))
return (true);
else
return (false);
}




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