# How to find particular highest salary from a table...

Here we discuss about to find "x" highest salary from a table.. There are so many options are available in sql server but this is best and easy way to find particular highest and lowest salary from a table...

Now-a-days many of our interviewers asking how to get 3rd highest salary from a table?

``SELECT MIN(SALARY) FROM SAMPLETABLE1 WHERE SALARY in (SELECT TOP 3 SALARY FROM SAMPLETABLE1)``

But this is not a correct way and we never get the exact result by using this query...

Let us see...

Here we create one sample table like SAMPLETABLE1

`CREATE TABLE SAMPLETABLE1 (ID INT IDENTITY,NAME VARCHAR(100),SALARY MONEY)`

and insert some values into it...

`INSERT INTO SAMPLETABLE1(NAME,SALARY) VALUES ('John',10000),('Cate',8000),('Arun',4000),('Billy',8000),('Raja',6000),('Kumar',8000),('William',9000),('Devi',3000)`

Then we write a simple query like this...

For Find "x" Highest salary
--=========================

`SELECT * FROM SAMPLETABLE1 A WHERE (SELECT COUNT(DISTINCT(SALARY)) FROM SAMPLETABLE1 B WHERE A.SALARY<=B.SALARY)=3`

Here 3 is third highest salary from a table it will display

OUTPUT
--------
ID NAME SALARY
-- ------ -------
2 Cate 8000.00
4 Billy 8000.00
6 Kumar 8000.00

If we change into 5 then it will display fifth highest salary from a table (i.e)

`SELECT * FROM SAMPLETABLE1 A WHERE (SELECT COUNT(DISTINCT(SALARY)) FROM SAMPLETABLE1 B WHERE A.SALARY<=B.SALARY)=5`

OUTPUT
--------
ID NAME SALARY
-- ------ -------
3 Arun 4000.00

If we change into 1 then it will display First Highest salary from a table (i.e)

`SELECT * FROM SAMPLETABLE1 A WHERE (SELECT COUNT(DISTINCT(SALARY)) FROM SAMPLETABLE1 B WHERE A.SALARY<=B.SALARY)=1`

OUTPUT
--------
ID NAME SALARY
-- ------ -------
1 John 10000.00

this is the simple method to find all the highest value from a table..

For Find "x" Lowest salary
--========================

To find first lowest salary no need to write a new query just change the symbol from "<" to ">"
(i.e)

`SELECT * FROM SAMPLETABLE1 A WHERE (SELECT COUNT(DISTINCT(SALARY)) FROM SAMPLETABLE1 B WHERE A.SALARY>=B.SALARY)=1`

it will display first lowest salary from a table

OUTPUT
--------
ID NAME SALARY
-- ------ -------
8 Devi 3000.00

To find second lowest salary just change "1" to "2" in our query....

`SELECT * FROM SAMPLETABLE1 A WHERE (SELECT COUNT(DISTINCT(SALARY)) FROM SAMPLETABLE1 B WHERE A.SALARY>=B.SALARY)=2`

we get
OUTPUT
--------
ID NAME SALARY
-- ------ -------
3 Arun 4000.00

likewise we change numbers from our query to find all level salaries..

`SELECT * FROM SAMPLETABLE1 A WHERE (SELECT COUNT(DISTINCT(SALARY)) FROM SAMPLETABLE1 B WHERE A.SALARY>=B.SALARY)=3`

OUTPUT
--------
ID NAME SALARY
-- ------ -------
5 Raja 6000.00

Another simple option is

`SELECT NAME,SALARY FROM(SELECT DENSE_RANK() OVER(ORDER BY SALARY DESC) AS HighestSalary,NAME,SALARY FROM SAMPLETABLE1)AWHERE HighestSalary=3`

OUTPUT
--------
ID NAME SALARY
-- ------ -------
2 Cate 8000.00
4 Billy 8000.00
6 Kumar 8000.00

Here too we get the same result....

DROP TABLE SAMPLETABLE1

Hope it is useful to all the beginners!!!!

Thanks and Regards,
Sri
Senior DB Developer,
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