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Resources » Code Snippets » SQL »

Using Dense_Rank in SQL server 2005


Posted Date: 14 Oct 2009    Resource Type: Code Snippets    Category: SQL
Author: KunalMember Level: Gold    
Rating: 1 out of 5Points: 7



What to do when the Rank function produces the gaps in the ranking system. for example if there is atie for 2nd rank than the rank function skips the 3rd rank and continues with 4th rank. what to do when you need all ranks witout any gaps


CREATE TABLE
Employee(FirstName VARCHAR(10),Salary INT,)

INSERT INTO Employee VALUES ('Ted',2300)
INSERT INTO Employee VALUES ('John',4000)
INSERT INTO Employee VALUES ('George',600)
INSERT INTO Employee VALUES ('Mary',1100)
INSERT INTO Employee VALUES ('Sam',1700)
INSERT INTO Employee VALUES ('Doris',600)
INSERT INTO Employee VALUES ('Frank',3800)
INSERT INTO Employee VALUES ('Larry',500)
INSERT INTO Employee VALUES ('Sue',2900)
INSERT INTO Employee VALUES ('Sherry',1100)
INSERT INTO Employee VALUES ('Marty',2300)

use this query

SELECT Dense_RANK() OVER (ORDER BY Salary) AS [Rank by Salary], FirstName,
Salary FROM Employee

output
Dense Rank by Age FirstName Age
-------------------- ---------- -----------
1 Larry 500
2 Doris 600
2 George 600
3 Mary 1100
3 Sherry 1100
4 Sam 1700
5 Ted 2300
5 Marty 2300
6 Sue 2900
7 Frank 3800
8 John 4000




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