CREATE FUNCTION dbo.ufn_Split(@String nvarchar(4000), @Delimiter char(1))
RETURNS @Results TABLE (value nvarchar(4000))
AS
--this function takes two parameters; the first is the delimited string, the second is the delimiter
==========================
BEGIN
DECLARE @INDEX INT
DECLARE @SLICE nvarchar(4000)
-- HAVE TO SET TO 1 SO IT DOESNT EQUAL Z
-- ERO FIRST TIME IN LOOP
SELECT @INDEX = 1
IF @String IS NULL RETURN
WHILE @INDEX !=0
BEGIN
-- GET THE INDEX OF THE FIRST OCCURENCE OF THE SPLIT CHARACTER
SELECT @INDEX = CHARINDEX(@Delimiter,@STRING)
-- NOW PUSH EVERYTHING TO THE LEFT OF IT INTO THE SLICE VARIABLE
IF @INDEX !=0
SELECT @SLICE = LEFT(@STRING,@INDEX - 1)
ELSE
SELECT @SLICE = @STRING
-- PUT THE ITEM INTO THE RESULTS SET
INSERT INTO @Results(value) VALUES(@SLICE)
-- CHOP THE ITEM REMOVED OFF THE MAIN STRING
SELECT @STRING = RIGHT(@STRING,LEN(@STRING) - @INDEX)
-- BREAK OUT IF WE ARE DONE
IF LEN(@STRING) = 0 BREAK
END
RETURN
END
select* from t_job where txt_location
in(select value from ufn_Split('kochi,iran,alw,irq',','))
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