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How to get file path using open file dialog control


Posted Date: 15 May 2008    Resource Type: Code Snippets    Category: C# Syntax
Author: Abhishek AryaMember Level: Diamond    
Rating: Points: 10



The following code sample shows how to get file path using open file dialog control


OpenFileDialog ofd = new OpenFileDialog(); 

string filename = ""; 
string path = ""; 

         if (ofd.ShowDialog() == DialogResult.OK) 
         { 
                    filename = System.IO.Path.GetFileName(ofd.FileName); 
                    path = System.IO.Path.GetDirectoryName(ofd.FileName); 
         } 

         MessageBox.Show(filename, "Filename"); 
         MessageBox.Show(path, "Directory");



Responses
Author: RamyaNaidu    06 Aug 2008Member Level: Silver   Points : 2
private void btn_Click(object sender, EventArgs e)
{
openFileDialog.InitialDirectory = @":D\\";
openFileDialog.Filter = "Text files (*.txt)|*.txt|" +
"DWGfiles (*.*)|*.*";
openFileDialog.FilterIndex = 1;

if (openFileDialog.ShowDialog() == DialogResult.OK)
{
MessageBox.Show(openFileDialog.FileName.ToString());
FileInfo File = new FileInfo("D:\\hhh.txt");
if (File.Exists)
{
StreamReader reader = new StreamReader(openFileDialog.FileName);
try
{
strFileName = openFileDialog.FileName;
txt.Text = reader.ReadToEnd();
}
catch (Exception ex)
{
MessageBox.Show(ex.Message);
return;
}
finally
{
reader.Close();
MessageBox.Show("File exists");

}
}
else
{
FileInfo MyFile = new FileInfo(@"D:\\hhh.txt");
MyFile.Create();
MessageBox.Show("File Successfully Created.");
}

}
}


Author: RamyaNaidu    06 Aug 2008Member Level: Silver   Points : 2
private void btn_Click(object sender, EventArgs e)
{
openFileDialog.InitialDirectory = @":D\\";
openFileDialog.Filter = "Text files (*.txt)|*.txt|" +
"DWGfiles (*.*)|*.*";
openFileDialog.FilterIndex = 1;

if (openFileDialog.ShowDialog() == DialogResult.OK)
{
MessageBox.Show(openFileDialog.FileName.ToString());
FileInfo File = new FileInfo("D:\\hhh.txt");
if (File.Exists)
{
StreamReader reader = new StreamReader(openFileDialog.FileName);
try
{
strFileName = openFileDialog.FileName;
txt.Text = reader.ReadToEnd();
}
catch (Exception ex)
{
MessageBox.Show(ex.Message);
return;
}
finally
{
reader.Close();
MessageBox.Show("File exists");

}
}
else
{
FileInfo MyFile = new FileInfo(@"D:\\hhh.txt");
MyFile.Create();
MessageBox.Show("File Successfully Created.");
}

}
}


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