| Author: Kiran Kumar Raju 23 Oct 2008 | Member Level: Silver | Rating:  Points: 6 |
Hi Tamil,
Please execute the below XSLT file. It will give you sorted xml data in a table with respect to Title.
XSLT file:
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:msxsl="urn:schemas-microsoft-com:xslt" exclude-result-prefixes="msxsl"
>
<xsl:output method="xml" indent="yes"/>
<xsl:template match="/">
<!--<xsl:copy>
<xsl:apply-templates select="@* | node()"/>
</xsl:copy>-->
<html>
<head>
<title>Sorting XML Data</title>
</head>
<body>
<table width="100%" border="1">
<thead>
<tr>
<td width="35%">
<B>Title</B>
</td>
<td width="35%">
<B>Company Name</B>
</td>
<td width="30%">
<B>City</B>
</td>
</tr>
</thead>
<tbody>
<xsl:for-each select="NewDataSet/*">
<xsl:sort select="title" order="ascending"></xsl:sort>
<tr>
<td>
<xsl:value-of select="Title"/>
</td>
<td>
<xsl:value-of select="CompanyName"/>
</td>
<td>
<xsl:value-of select="CityName"/>
</td>
</tr>
</xsl:for-each>
</tbody>
</table>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
Thanks
Kiran Kumar Raju
|