| Author: Karthikeyan S 30 Aug 2008 | Member Level: Gold | Rating:  Points: 4 |
Hi,
If your form name is "LoginForm" then
in the code page write below coding:
Public Sub LoginForm()
MsgBox("Constructor is Called Successfully.")
End Sub
Note: If you don't know form name see the text nearer to the keyword 'Inherits' or 'imports'.
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