| Author: Nagarajan 12 Aug 2008 | Member Level: Gold | Rating:  Points: 3 |
Try this , instead of creating a FileDialog in coding, try dragging a FileDIalog control in the design view iteself,
so that you can use it in your code with out instantiating it.
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| Author: ksdkarthikeyan 12 Aug 2008 | Member Level: Silver | Rating: Points: 4 |
dim value as boolean
copy below code and paste in Load events
value = Control.CheckForIllegalCrossThreadCalls
Control.CheckForIllegalCrossThreadCalls = False
i fixed the error..
this is useful for others whose faced this error thank you.
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| Author: Geetha 12 Aug 2008 | Member Level: Gold | Rating: Points: 6 |
Private FileName As String
'declaring filename that will be selected
Dim sr As StreamReader
'streamreader is used to read text
Try
With OpenFileDialog1
'With statement is used to execute statements using a particular object, here,_
'OpenFileDialog1
.Filter = "Text files (*.txt)|*.txt|" & "All files|*.*"
'setting filters so that Text files and All Files choice appears in the Files of Type box
'in the dialog
If .ShowDialog() = DialogResult.OK Then
'showDialog method makes the dialog box visible at run time
FileName = .FileName
sr = New StreamReader(.OpenFile)
'using streamreader to read the opened text file
RichTextBox1.Text = sr.ReadToEnd()
'displaying text from streamreader in richtextbox
End If
End With
Catch es As Exception
MessageBox.Show(es.Message)
Finally
If Not (sr Is Nothing) Then
sr.Close()
End If
End Try
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