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Help need with Regular Expression in C#

Posted Date: 11 Jan 2008      Posted By:: Manoj V     Member Level: Bronze    Member Rank: 0     Points: 2   Responses: 2



I have a string s="kYY2034924324YYYYYYYGdsfjldksjdsjfflYYYYYYY1234YY".

I need to replac YY ( NOT YY in YYYYYYY) with 'xx'.
i.e output must be "kxx2034924324YYYYYYYGdsfjldksjdsjfflYYYYYYY1234xx"

Pls help. Urgent.


Responses
#178436    Author: Subhashini Janakiraman      Member Level: Silver      Member Rank: 1714     Date: 11/Jan/2008   Rating: 2 out of 52 out of 5     Points: 2

Iam just puzzled by the question.Here is my answer.Here when you execute the procedure you will get the solution in vb.net
In a procedure by name change2,
public sub change2()
dim s as string="kYY2034924324YYYYYYYGdsfjldksjdsjfflYYYYYYY1234YY".
dim arr(s.length-1) as char
dim i as integer
dim str as string=""
for i=0 to s.length-1
arr(i)=s.substring(i,1)
next
Do while(i<=s.length-1)
if arr(i)="Y" then
if arr(i+1)="Y" then
if arr(i+2)<>"Y" then
arr(i)="X"
arr(i+1)="X"
endif
endif
endif
i=i+1
Loop
for i=0 to s.length-1
str=str& arr(i)
Next
textbox1.text=str
end sub

IF you want the solution in C#.net
public static void change2()
{
string s="kYY2034924324YYYYYYYGdsfjldksjdsjfflYYYYYYY1234YY";
int i;
char[] arr=new char[s.length];
while(i<s.length)
{
char a=Convert.toChar(s.substring(i,1));
arr[i]=a;
i=i+1;
}
for(i=0;i<s.length-3;i++)
{
if(arr[i]=='Y')
{
If(arr[i+1]=='Y')
{
if(arr[I+2]!='Y')
{
arr[i]='x';
arr[i+1]='x';
}
}
}
i=i+1;
}
for(i=0;i<s.length;i++)
{
string str=str+arr[i];
}
Console.WriteLine("The new string is "+str);
}
Dear Manoj,
When I tried this program in computer it did not work out.Sorry.Hope you will find suitable solution .

 
#178451    Author: Manoj V      Member Level: Bronze      Member Rank: 0     Date: 11/Jan/2008   Rating: 2 out of 52 out of 5     Points: 2

Thank you very much for providing the solutin, Subhashini Janakiraman.

 
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